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3x^4/3+5=53
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The answer should be 8 and -8....
subtract 5 \[3x^{\frac{4}{3}}=48\] divide by 3\[x^{\frac{4}{3}}=16\]
then compute \[x=16^{\frac{3}{4}}\] or \[x=-16^{\frac{3}{4}}\]
fourth root of 16 is 2, and \(2^3=8\) for the first one
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