Question

4rs-2s-3(rs+1)-2s
Simplify.

Answer 1

distribute -3 to get 4rs -2s-3r+3-2s

Answer 2

put matching together 4rs-3rs-2s-2s-3

Answer 3

combine like terms 1rs -4s+4 of rs-4s+4

Answer 4

I got 1rs+(-3) as my answer

Answer 5

you made an "operations with integers" mistake show me your steps

Answer 6

4rs-2s-3(rs+1)-2s
I distributed 3 to rs & 1.

4rs-2s-3rs+(-3)-2s
I combined like terms (4rs+(-3rs)= 1rs & -2s-2s= 0

So my answer is 1rs+(-3)

Answer 7

-2s-2s does not equal 0

Answer 8

but I did make mistakes too here its is

Answer 9

4rs -2s-3rs+3-2s
so (4rs-3rs) = 1rs
(-2s-2s)=-4s
3 =3
so its
rs-4s+3
that is a common mistake that students thing -2s-2s = 0 because they remember to negatives make a positive but that is only when you multiply them

Answer 10

can you help me on my next one?

Answer 11

yes

Answer 12

8y-2z-(y-z)+3yz

Answer 13

8y-2z-(y-z)+3yz
when you see -(y-z) it means -1(y-z) so you distrib the -1

Answer 14

so to get 8y-2z-y+z+3yz

Answer 15

now combine like terms