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When I have \[y''+y'-2y=sin2x\] \[y_p(x)=Acos2x+Bsin2x\]?
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yep
thanks
oh I guess I suck at simple algebra... I can't seem to be able to simplify this: \[(-4Asin2x-4Axcos2x+4Bcos2x-4Bxsin2x)\]\[+(2Acos2x-2Axsin2x+2Bsin2x+2Bxcos2x)\]\[-2(Axcos2x+Bxsin2x)=sin2x\]
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