he diameter of a circle drawn on a coordinate grid has one of its end points at (-3, 2) and the other end point at (6, -4). Leena performed the steps shown to find the length of the diameter.

Step 1. x1 = -3, y1 = 2, x2 = 6, y2 = -4
Step 2. Distance =
Step 3. Distance =
Step 4. Distance =
Step 5. Distance is approximately 6.71

Question

he diameter of a circle drawn on a coordinate grid has one of its end points at (-3, 2) and the other end point at (6, -4). Leena performed the steps shown to find the length of the diameter.


Step 1.  x1 = -3, y1 = 2, x2 = 6, y2 = -4
Step 2. Distance = 
Step 3. Distance = 
Step 4. Distance = 
Step 5. Distance is approximately 6.71

anonymous · Answer

$$\begin{align} d&=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2} \&=\sqrt{(-4-2)^2+(6-(-3))^2} \&= \end{align}$$

anonymous · Answer

so what is the answer?

anonymous · Answer

Well, it comes to 10.82. I don't know which part i did wrong. Lol

anonymous · Answer

okay