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OpenStudy (anonymous):
2-tan(theta)/2csc(theta)-sec(theta)
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OpenStudy (anonymous):
yes?...
OpenStudy (anonymous):
= 2cos(theta)-sin(theta /(cos(thetha))/ (2 cos(theta)-sin(theta)/sin(theta)cos(theta) = 2cos(theta)-sin(theta)* (sin(theta)cos(theta))/ cos(theta)* (2cos(theta)-sin(theta ) =sin(theta)
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