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How do you solve this Find two consecutive Even integers such that the lesser added to three times the greater gives a sum of 46
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I don't think this problem's correct :) Or i'm miscalculated.
The integers have to be even
oh sorry, i think you already know the answer, but okay: 2n and 2n+2 2n+3(2n+2)=46 2n+6n+6=46 8n=40 n=5 :D
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