Question

How do you solve
When the lesser of two consecutive integers is added to three times the greater the result is 43

Answer 1

Let x and x + 1 be the consecutive integers.
x is the less one and x+ 1 is the greater one.

Three times the greater is written in symbols as 3( x + 1 )

the lesser of two consecutive integers is added to three times the greater the result is 43

Translating the words gives the following:

x + 3 ( x + 1 ) = 43
x + 3x + 3 = 43
4x + 3 + 43
4x = 40
x = 10
Lesser integer is 10; the greater integer is 11.