Question

How do you solve
If the sum of three consecutive even integer is 60 what is the first of the three even integers

Answer 1

\[n, n+2, n+4\]
addition results to 60
\[\left( n \right)+\left( n+2 \right)+\left( n+4 \right)=60\]
\[3n + 6 = 60\]
\[3n =54 \]
\[n= \frac{ 54 }{ 3 }\]

Answer 2

\[n = 18\]
the numbers are 18, 20, 22