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f(x)=2x^2-5x-2 and g(x)=9-3x a) f (3) b) g (-3) c) f (-2) d) (1/3) e) f ( -5)
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a) substitute x = 3 for function f(x) b) substitute x = -3 for function g(x) and so on. try them first please. tell me if you don't get it is d) missing something?
wait im still lost subutie for wea
\[f(x)=2x^2-5x-2\]now try x = 3 for the equation above
-> 2(3)^2 - 5(3) - 2
what do i do after that
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solve it 3^2 then times 2, then minus 5 times 3, then minus 2
is it 22
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