Question

A truck covers 40.0 m in 8.50 s while smoothly slowing down to a final velocity of 2.80 m/s.
(a) Find the truck's original speed.
(b) Find acceleration

Answer 1

Here s =40.0 m
t = 8.50 s
v = 2.80 m/s

(a) original speed = initial speed = u
\[s = \frac{ u+v }{ 2 } \times t\]

(b) \[a = \frac{ v-u }{ t }\]