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Solve the given inequality. Write the solution set using interval notation, then graph it.
1/3x-2<1/4x+4
What I know is that the LCD of 3 & 4 is 12 so I get:
12(1/3x-2)<12(1/4x+4)
12/36x-24<12/48x+48
3x-24<4x+48
3x-72<4x
-72
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\[\frac{ 1 }{ 3 }x-2<\frac{ 1 }{ 4 }x+4\]
??
That's right.
Then I multiplied by 12 on both sides
4x-24<3x+48
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add 24 to both sides next
then subtract 3x from both sides
x<72
Thats what I got
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