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lim x->4 (√x-2)(√x^3-8)
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did you means lim as x->2 ?
nope it's definitely x -> 4 !
ah, is your equation \[(\sqrt{x} -2)(\sqrt{x^3} -8)\]
yes
well it's (x√−2) / (x3−−√−8)
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then the limit is just zero, plug in four and you'll see...
the answer is supposed to be (1/12) :/
sorry meant to say 'four' not 'zero'
what's the square root of 4?
2..
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(2-2) =?
nvm i was just writing out my equation wrong! thanks though :)
sure
k
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