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sin^4x+cos^4x=1-2cos^2x+2cos^4x hey can anyone do this trig identity? You'll be awesome :)
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Sin^4x=(sin^2x)^2=(1-cos^2x)^2=1-2cos^2x+cos^4x therfore Left side of eqn is = 1-2co^2x+cos^4x+cos^4x= RHS
you have the answer, why are you bumping the question?
maybe he want know how to prove...
Sorry.. It was a little confusing, but I'll work with I have.
How did he get 1-cos^2x?
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sin^2(x)= 1-cos^2(x) is fundamental identity of trig
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