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Physics 6 Online
OpenStudy (anonymous):

What is the net gravitational force acting on planet Z?

OpenStudy (anonymous):

OpenStudy (anonymous):

It's number 56

OpenStudy (anonymous):

sorry dude, too advanced for me :(

OpenStudy (anonymous):

ahah see what i mean :(

OpenStudy (ujjwal):

Find the gravitational pull by individual planets (X and Y) on Z and just add them up since the force will act in same direction!

OpenStudy (anonymous):

That actually made sense, ill give it a shot. Thannks :)

OpenStudy (anonymous):

Kinda small but hope it will do

OpenStudy (ujjwal):

Doesn't your book provide an answer?

OpenStudy (ujjwal):

Seems ok! Did you add both forces?

OpenStudy (anonymous):

Yes i did, I did that on the side, i didn't really showed the steps, i just wrote the number. It does, but it's wrong. Which is why I thought you can do the question. If you get the same answer, perhaps the book is wrong.

OpenStudy (ujjwal):

So, the books' answer is more than what you get? right?

OpenStudy (anonymous):

The book's answer is 6.16 x 10 ^17N. So less than what I got.

OpenStudy (ujjwal):

change Km to meter!

OpenStudy (anonymous):

OHHHHHHHHHHH. Thanks :)

OpenStudy (ujjwal):

welcome!

OpenStudy (anonymous):

I still can't get the answer @ujjwal I dunno I'm off by a bit. i got 4.53*10^17

OpenStudy (ujjwal):

Oops! seems like i missed something.. you should add the gravitational force of attraction between X and Y too.. Of course they are also attracted to each other.. Sorry, I forgot to mention it earlier.. And yeah again don't forget to convert km to meters!

OpenStudy (anonymous):

So wait do I add the force attraction between X and Y, Y and Z..what about X and Z? Oh and yes I did

OpenStudy (ujjwal):

add all three of them!

OpenStudy (anonymous):

I only added Y and Z and X and Z, and got the answer. So i guess there's no need to add all three of em :P thanks tho, I understood it well:)

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