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Mathematics 15 Online
OpenStudy (anonymous):

Fill in the missing term so that the quadratic equation has a graph that opens up, with a vertex of (– 3, – 25), and x intercepts at x = -8 and x = 2. y = x^2 + 6x − ___

OpenStudy (cwrw238):

the last term is the product of the zeros of this function

OpenStudy (anonymous):

soooooo...................................

OpenStudy (cwrw238):

so multiply

OpenStudy (anonymous):

what do i multiply

OpenStudy (cwrw238):

the zeros ( = the x -intercepts)

OpenStudy (anonymous):

so (x+8)(x-2)?

OpenStudy (cwrw238):

when y = o x = -8 and +2

OpenStudy (cwrw238):

yes

OpenStudy (anonymous):

-16?

OpenStudy (cwrw238):

so expanding those brackets gives what as the last term?

OpenStudy (cwrw238):

yes

OpenStudy (anonymous):

ok thanks

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