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Can someone go over sin x= -.5 -inf
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@satellite73
@Hero
Well, we need to isolate x first
\[x=\sin^{-1} (-.5)\] i got there. but i don't know what to do about the intervals.
@dpaInc help please?
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do you have a trig table? Look up the degree or radian where sine is -1/2
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