Ask your own question, for FREE!
Mathematics 18 Online
OpenStudy (anonymous):

you roll two fair dice. What is the probability of one of the dice showing 5 or the sum being at least 8

OpenStudy (anonymous):

please help!

OpenStudy (lgbasallote):

first...draw the dice combinations (1,1) (1,2) (1,3) (1,4) (1,5) (1,6) (2,1) (2,2) (2,3) (2,4) (2,5) (2,6) (3,1) (3,2) (3,3) (3,4) (3,5) (3,6) (4,1) (4,2) (4,3) (4,4) (4,5) (4,6) (5,1) (5,2) (5,3) (5,4) (5,5) (5,6) (6,1) (6,2) (6,3) (6,4) (6,5) (6,6) got it?

OpenStudy (anonymous):

i thought it was 20/36, but that was wrong

OpenStudy (lgbasallote):

the probability of one of the dice showing 5 is (5,1) (5,2) (5,3) (5,4) (5,5) (5,6) so 6/36 then the probability of sum of 8 is (2,6) (3,5) (4,4) (5,3) (6,2) so 5/36

OpenStudy (lgbasallote):

now add 6/36 + 5/36

OpenStudy (lgbasallote):

what do you get?

OpenStudy (anonymous):

11/36 is wrong

OpenStudy (lgbasallote):

oh wait...

OpenStudy (lgbasallote):

i forgot another 5/36

OpenStudy (anonymous):

its 6/36+5/36+3/36

OpenStudy (lgbasallote):

should be 6/36 + 6/36 + 5/36

OpenStudy (anonymous):

no, cuz 3,5 and 5,3 is counted

OpenStudy (anonymous):

17/36 is wrong

OpenStudy (lgbasallote):

really?

OpenStudy (anonymous):

yep

OpenStudy (anonymous):

its 14/36?

OpenStudy (lgbasallote):

yeah i think @pizzapi is right

OpenStudy (lgbasallote):

3/36 because the others are already counted

OpenStudy (anonymous):

14/36 is wrong

OpenStudy (anonymous):

3/36 is wrong

OpenStudy (lgbasallote):

no..that wasn't what i meant

OpenStudy (lgbasallote):

this is bizarre. it should be 12/46 + 5/36....

OpenStudy (anonymous):

(1,5) (2,5) (2,6) (3,5)(4,4) (4,5) (5,1) (5,2) (5,3) (5,4) (5,5) (5,6)(6,2) (6,5)

OpenStudy (lgbasallote):

ahh got it 11/36 + 5/36

OpenStudy (lgbasallote):

so it should be 16/36

OpenStudy (lgbasallote):

or 4/9

OpenStudy (anonymous):

that is wrong.. i have unlimited trys so it tells me if i get it right or wrong

OpenStudy (lgbasallote):

did you try 4/9?

OpenStudy (anonymous):

ya

OpenStudy (anonymous):

try 13/36

OpenStudy (anonymous):

wrong

OpenStudy (anonymous):

it was 19/36

OpenStudy (lgbasallote):

ugh AT LEAST 8...didn't see that 11/36 + 15/36 should be 26/36

OpenStudy (lgbasallote):

so should be 13/18

OpenStudy (anonymous):

it was 19/36

OpenStudy (lgbasallote):

how?

OpenStudy (lgbasallote):

are you sure you asked the right question?

OpenStudy (valpey):

(1,5) (2,5) (2,6) (3,5) (3,6) (4,4) (4,5) (4,6) (5,1) (5,2) (5,3) (5,4) (5,5) (5,6) (6,2) (6,3) (6,4) (6,5) (6,6) Is 19 solutions out of 39.

OpenStudy (valpey):

*out of 36

OpenStudy (anonymous):

ic, didn't read the "at least 8" part

OpenStudy (valpey):

Rough night @lgbasallote ?

OpenStudy (lgbasallote):

but it says probability of one die being 5 or sum of at least 8 so that means it should be P(one die 5) + P(sum at least 8) right?

OpenStudy (valpey):

uh, minus P(one die 5 and sum at least 8)

OpenStudy (valpey):

P(A or B) = P(A) + P(B) - P(A and B)

OpenStudy (lgbasallote):

hmm yeah. rough night

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!