the probability of one of the dice showing 5 is (5,1) (5,2) (5,3) (5,4) (5,5) (5,6) so 6/36
then the probability of sum of 8 is (2,6) (3,5) (4,4) (5,3) (6,2) so 5/36
OpenStudy (lgbasallote):
now add 6/36 + 5/36
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OpenStudy (lgbasallote):
what do you get?
OpenStudy (anonymous):
11/36 is wrong
OpenStudy (lgbasallote):
oh wait...
OpenStudy (lgbasallote):
i forgot another 5/36
OpenStudy (anonymous):
its 6/36+5/36+3/36
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OpenStudy (lgbasallote):
should be 6/36 + 6/36 + 5/36
OpenStudy (anonymous):
no, cuz 3,5 and 5,3 is counted
OpenStudy (anonymous):
17/36 is wrong
OpenStudy (lgbasallote):
really?
OpenStudy (anonymous):
yep
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OpenStudy (anonymous):
its 14/36?
OpenStudy (lgbasallote):
yeah i think @pizzapi is right
OpenStudy (lgbasallote):
3/36 because the others are already counted
OpenStudy (anonymous):
14/36 is wrong
OpenStudy (anonymous):
3/36 is wrong
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