Question

3x+2[5-4(x+1)]=6(x-3)+2(x+5)

Answer 1

distribute the 4, distribute the 6, distribute the 2

Answer 2

I solved and got x=16/13th's

Answer 3

I got x=6/13

Answer 4

I got 10/13.

Answer 5

at least we all got the same denominator! haha

Answer 6

True...now to find the numerator

Answer 7

Right on. Who wants to post his or her work first for the others to trouble-shoot?

Answer 8

I got 3x=2[5-4x-1]=6x-18+2x+10

Answer 9

*3x+2

Answer 10

then 3x+10-8x-2=6x-18+2x+10

Answer 11

3x+10-8x-4=6x-18+2x+10

Answer 12

ohhh -4 is where I messed up.

Answer 13

I got 3x=2[5-4x-1]=
=============
3x + 2[5 - 4x - 4] =

Answer 14

@oholmes --> And, then ... ?

Answer 15

one second

Answer 16

Im confused I got 2/5th's

Answer 17

okay...so we have 3x+2(5-4x-4)=6x-18+2x+10. Do we agree on that part?

Answer 18

yees

Answer 19

lets work with the left side first...

Answer 20

okay I got 3x-10-8x-8=

Answer 21

3x+10-8x-8 after we distribute the 2

Answer 22

ok

Answer 23

combine like terms

Answer 24

-5x+2

Answer 25

3x-8x and 10-8

Answer 26

yep. now lets work on the right side

Answer 27

6x-18+2x+10

Answer 28

ok, 8x-8

Answer 29

-5x+2=8x-8

Answer 30

subtract 8x from both sides

Answer 31

i got 10/13

Answer 32

-13x+2=-8; subtract 2 from from both sides

Answer 33

10/13 is the answer I got.

Answer 34

good job!

Answer 35

my adding/subtract was off! Sorry! :)

Answer 36

Let's work another problem together in a new thread. @oholmes Post a question if you like.