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Mathematics 20 Online
OpenStudy (anonymous):

Look at the figure below. Which expression is equal to AB/RQ? A.PQ/PB B.PA/PR C.PQ/PA D.AR/AB

OpenStudy (wwe123):

there is no pic

OpenStudy (anonymous):

OH OKAY HOLD ON

OpenStudy (anonymous):

OpenStudy (aravindg):

PA/PR

OpenStudy (anonymous):

Can you explain how got that since the second one is not a triangle

OpenStudy (aravindg):

i just used the property of similiar triangle

OpenStudy (aravindg):

i took two triangles PAB and PRQ , now angle A is common to them

OpenStudy (aravindg):

As the lines are parallel the corrresponding angles will be equal |dw:1347986907423:dw|

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