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Look at the figure below. Which expression is equal to AB/RQ? A.PQ/PB B.PA/PR C.PQ/PA D.AR/AB
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there is no pic
OH OKAY HOLD ON
PA/PR
Can you explain how got that since the second one is not a triangle
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i just used the property of similiar triangle
i took two triangles PAB and PRQ , now angle A is common to them
As the lines are parallel the corrresponding angles will be equal |dw:1347986907423:dw|
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