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Tony and Belinda have a combined age of 56. Belinda is 8 more than twice Tony’s age. How old is each?
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tony is 16, belinda is 40
let tony's age be x. so Belindas age = 56-x. Belinda is 8 more than twice Tony’s age. so 56-x = 2x+8 can u solve this and find x ?
@Turner Please provide more than just the answer. Try to work with the asker as hartnn has.
56 - 8 = 48 48 / 3 = 16 (tony's age) 16 x 2 + 8 = 40 (belinda's age)
thanks :p
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np (:
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