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OpenStudy (anonymous):
Solve for x: the quantity of x plus 20 over 2 = 3x
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OpenStudy (anonymous):
\[\frac{ x+20 }{ 2 }=3x\] \[2(\frac{ x+20 }{ 2 })=3x(2)\] This cancels out the 2 in the fraction \[x+20=6x\] -x -x 20 = 5x /5 /5 x = 4
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