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Find the integral xtan(4x) dx
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Try integration by parts.
I did and I got stuck
That is,\[\int u(x)v'(x)\,dx=u(x)v(x)-\int u'(x)v(x)\,dx.\]
i already know that i just am stuck on a certain part
On which part are you stuck?
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I get x ln(sec(4x)/4) then im stuck after that
i need the integral at ln(sec(4x)/4)
I believe you mean \(\frac14\ln\cos4x\).
no i mean what i typed
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