Question

(x-12)^2=16

Answer 1

(x-12)^2=16

(x-12)^2 - 16 = 0

z^2 - 16 = 0 .... Let z = x - 12

(z-4)(z+4) = 0

(x - 12 - 4)(x - 12 + 4) = 0 ... Plug in z = x - 12

Keep going to solve for x

Answer 2

im doing equation by extracting square roots

Answer 3

you can do it this way

Answer 4

(x-12)^2=16

x-12=sqrt(16) or x-12=-sqrt(16)

x-12 = 4 or x-12 = -4

Answer 5

thats what i got

Answer 6

keep going to solve for x