Question

what is the limit of (3-x^2)/(x-3) as x approaches 3?

Answer 1

\[ \large \lim_{x\to3}\frac{3-x^2}{x-3}=\frac{3-3^2}{3-3}=\frac{-6}{0}= \]

Answer 2

the answer is dne? when i graphed it it was -1
the thing is is that i am not supposed to use a graphing calculator to solve it

Answer 3

yes. it doesn't exist.