Question

how far will a freely falling object fall from rest in five seconds? six seconds?

Answer 1

Just use the kinematic equation:\[d=V_0t+\frac{1}{2}at^2\]and solve it for each time t.

Answer 2

Since it states "from rest", it should be clear that V0 should be 0...so that simplified to:\[d=\frac{1}{2}at^2\]In case it's not clear, a=acceleration due to gravity (-9.8m/s^2).

Answer 3

dude please just give me the answer i feel freaking over whelmed with homework and its taken me 2 hours just to do 12 question...... im gonna talk to my teacher next time i see him

Answer 4

and see if i i can get some alterations to the class for me .... XD

Answer 5

Giving you the answer directly isn't going to help at all. In fact, it'll just make things worse, because you'll have moved ahead in class without understanding. Sometimes it's just going to be hard work. There are single problems that I've worked on for over two hours. The good news is, now they're easy to me. You can get there, too. If it's hard, it just means you need more practice. Go out and look for supplemental books like the Schaum's guides, where you can see worked exercises. It'll help a ton.

Answer 6

Dude ....... I'm gonna fail Physics..... im in 12th grade 18 yrs old I should be graduated already!!! SERIOUSLY Sucks!!!

Answer 7

and Schaums Guides???

Answer 8

and the thing is im already confused as shiz and its only the first month of School!!!!

Answer 9

Im just gonna quit doing my homework and talk to my teacher next time i see him! ..... Cause this aint gonna work for me /: Im a very slow learner when it comes to almost everything Especially Anything School Related I take SOOOOO many Notes and Still have a hard time in class/Homework/Tests /:

Answer 10

I would suggest not to give up. Try watching some online videos...there are tons of them out there. Here's a popular site for students which has tons of physics videos which are easy to follow:

http://www.khanacademy.org/science/physics

Since you're doing motion stuff, click on the "Mechanics" link

Answer 11

Thanks Soooo Much for that Link/Website seriously Helping right now!! :)

Answer 12

yw :)