Ask your own question, for FREE!
Mathematics 17 Online
OpenStudy (anonymous):

State whether the graph of the function is a parabola. If the graph is a parabola, find the parabola's vertex. f(x)=x^2-6x+2

OpenStudy (anonymous):

vertex at x axis or y?

OpenStudy (anonymous):

y-axis. the answer has to be an ordered pair

OpenStudy (across):

A parabola's vertex happens at the point where its derivative is equal to zero.

OpenStudy (across):

Do you know what I'm talking about?

OpenStudy (anonymous):

\(\large f(x)=x^2-6x+2 \) you'll need to complete the square to get your function into this form: \(\Large f(x) = a(x-h)^2+k \) where (h, k ) is your vertex.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!