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What is the factored form of the expression?
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\[3x ^{2} + 8x – 16\]
A. (3x + 4)(x – 4) B. (3x + 4)(x + 4) C. (3x – 4)(x – 4) D. (3x – 4)(x + 4)
\[3x^2+ 12x - 4x - 16\] \[3x \left( x+4 \right) - 4\] \[\left( 3x+4 \right)\]
Well, 3x^2 + 8x - 16 1 * 16, 2 * 8, 4 * 4, all go into 16, And only 1 * 3 go into 3, So, what works? (3x - 4)(x + 4 )
Thanks, @Kyle15
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3x(x+4)-4(x+4)
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