Please help me!! Greatly appreciated.

This is my last question and I can't seem to get it.

On January 1, 2010, Chessville has a population of 50,000 people. Chessville then enter a period of population growth. Its population increases 7% each year. On the same day, Checkersville has a population of 70,000 people. Checkersville starts to experience a population decline. Its population decreases 4% each year. During what year will the population of Chessville first exceed that of Checkersville?

Question

Please help me!! Greatly appreciated.

This is my last question and I can't seem to get it.

On January 1, 2010, Chessville has a population of 50,000 people. Chessville then enter a period of population growth. Its population increases 7% each year. On the same day, Checkersville has a population of 70,000 people. Checkersville starts to experience a population decline. Its population decreases 4% each year. During what year will the population of Chessville first exceed that of Checkersville?

anonymous · Answer

chessville is Calclated by 50000 times 1.07 times t (we dont know the time)
1.07 because thats 100% plus 7%
Checkerville is 70000 times 1.04 times
1.04 because its 100% plus 4%.
since we want to know when when Chessville is > Checkerville
so solve this
$$50000\times1.07\times t>70000\times1.04 \times t$$

anonymous · Answer

the t you get is how many years from 2010 checkerville is more so add it to 2010

anonymous · Answer

TAKEBACKMATH is wrong

anonymous · Answer

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