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x=2y+3z if your solving for y???
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Subtract 3z both sides
\[\large{x-\color{red}{3z}=\color{blue}{2y+3z}-\color{red}{3z}}\]
\[\large{\color{blue}{x-3z}=2y}\] \[\large{\frac{x-3z}{2}=\frac{2y}{2}}\]
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