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Mathematics 6 Online
OpenStudy (anonymous):

4r < –12

mathslover (mathslover):

divide both sides by 4

OpenStudy (bahrom7893):

i meant r < -3

mathslover (mathslover):

\[\large{\frac{4r}{4}<\frac{-12}{4}}\]

OpenStudy (anonymous):

why divide?

mathslover (mathslover):

\[\large{\frac{\cancel{4}^1 r}{\cancel{4}^1}<\frac{\cancel{-12}^{-3}}{\cancel{4}^1}}\]

mathslover (mathslover):

so that we can cancel 4 there in LHS

mathslover (mathslover):

as we want to "solve for r"

OpenStudy (anonymous):

soo.. i got -3?

mathslover (mathslover):

yes

mathslover (mathslover):

r<-3

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