Question

Factor trinominal times a binomial
equation in the comments

Answer 1

\[\left( 2x+4y+7 \right)\left( 5x+8 \right)\]

Answer 2

@ganeshie8

Answer 3

is it 'factor' or 'multiply' ?

Answer 4

you have to factor it. but its presented as a multiplication question.

Answer 5

hmm interesting.. its already in factored form i guess we cant factor it any further

Answer 6

i think it might be multiplying it though. the question is:
7.How about multiplying a trinomial times a binomial?

Answer 7

yea this makes sense :)

Answer 8

just have to multiply..

Answer 9

you familiar wid multuplying these right ?

Answer 10

somewhat

Answer 11

\((2x+4y+7)(5x+8)\)

\((\color{green}{2x}+4y+7)(\color{green}{5x+8})\)

Answer 12

first distribute 2x

Answer 13

then 4y
and lastly 7

Answer 14

in between them, would i use ()+()+() or just ()()()?

Answer 15

thats right ! in between we add. () + () + ()

Answer 16

\((\color{green}{2x}+4y+7)(\color{green}{5x+8}) \)

\(10x^2 + 16x + 20xy + 32y + 35x + 56 \)

Answer 17

see if above makes sense

Answer 18

\[\left( 10x^{2}+16x \right)+\left( 20xy+24y \right)+\left( 35x+56? \right)\]

Answer 19

thats almost right !! except for \(24y\)

Answer 20

i mistyped it. lool. its (20xy+32)

Answer 21

right ! now remove ()

Answer 22

and see if any like terms are there

Answer 23

16x and 35x and thats it.

Answer 24

yup :)

Answer 25

add them and write it in order

Answer 26

\[(10x^{2}+51x+20xy+24y+56)\]

Answer 27

\(\left( 10x^{2}+16x \right)+\left( 20xy+32y \right)+\left( 35x+56? \right) \)

\(10x^{2}+16x +20xy+32y +35x+56 \)

\(10x^{2}+20xy +51x+32y + 56 \)

Answer 28

again 24y. ...

Answer 29

if we ignore that 24y mistype, your final polynomial looks good except for one thing

Answer 30

\[(10x^{2}+51x+20xy+32y+56)\]

Answer 31

20xy order is more

Answer 32

so you have to move it to left,

Answer 33

and 51x to right.. swap 20xy and 51x