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HELP find value
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@hartnn help?
using a property in right triangle : BD^2 = 7*11 BD = ?
bd = 77^2?
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lol! no :P
D:
\(BD^2=7*11 \\ BD =\sqrt{77}=?\)
8.77
wait keep that as \(\sqrt{77}\) now apply pythagoras in BDC what do u get ?
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wait what???
confused!!!
@hartnn
just apply pythagoras in triangle BDC, can u ?
no idk how lol just explain and ill try to
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@hartnn
pythagoras! \(a^2+b^2=c^2 \\ BD^2+BC^2=BC^2 \\7^2+77=m^2\) can u find m now ?
126!!!!
sorry BD^2 + DC ^2=BC^2
126?
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yup, \(\sqrt{126}\) D.
ohhhh lol
help me solve this one plz?
just show me step by step
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new question, new post.
that is lengthy!
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