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A skier descends a mountain at an angle of 35.0º to the horizontal. If the mountain is 235 m long, what are the horizontal and vertical components of the skier's displacement? (Use trigonometry to solve.)
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Okay, thanks for that :) Not good with graphs.. Lol. But after I do my math, those are my answers? & How do you know when to use cos & sin? Thanks!
this is usual trigonometry p = h sin(theta) b = h cos(theta)
Oh okay. Well I haven't taken trig yet, so it's kind of difficult for me because I have to bridge that gap. Thanks so much!!
yw
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