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Mathematics
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lim as x -> infinity ((e^-7x) cos x)
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how?
I can't give you any method rather than this logic. No matter how the value of x is big cos(x) is between -1and 1. Thus forget about cos(x) and find the limit for e^-7x. What do you think?
That's what I was thinking more or less, though I had things a little backwards. Thank you!!
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