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Physics 22 Online
OpenStudy (anonymous):

2. An object is launched straight up. The object attains a height of 107 m after 2.50 s. a. What was the initial velocity? b. When (i.e. how long after launch) will the object have a speed of 20 m/s on the way back down?

OpenStudy (anonymous):

I have answer to the first question. i am not sure about second, how do you get the time.

OpenStudy (anonymous):

use Vf = Vi -a*t -20 = (whatever you found for Vi) -9.8*t solve for t

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