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write an equation for each tangent to the curve y = 1 / (x - 1) that has slope -1
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take the derivative, set it equal to one, solve the quadratic
1 or -1?
\[-\frac{1}{(x-1)^2}=-1\] \[(x-1)^2=1\] etc
oh sorry i meant \(-1\) as you wrote
\[(x-1)^2=1\] \[x-1=1\implies x=2\] or \[x-1=-1\implies x=0\]
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ok. and now i need to write an equation for each
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