In 1976, Gerald Hoagland drove a car over 8.0 ´ 102 km in reverse. Fortunately for Hoagland and motorists in general, the event took place on a special track. During this drive, Hoagland’s average velocity was about -15.0 m/s. Suppose Hoagland decides during his drive to go forward. He applies the brakes, stops, and then accelerates until he moves forward at same speed he had when he was moving backward. How long would the entire reversal process take if the average acceleration during this process is +2.5 m/s2?

Question