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For what values of k is f(x) continuous? 3x^2-11x-4 x<=4 kx^2-2x-1 x>4
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when x = 4, f(x) must be 0
k*4^2-2*4-1=0
there's an alternative method...
which is kinda what i did, but i skipped steps
3x^2-11x-4, when x<=4.. plug in 4 into that equation: 3*4^2-11*4-4=3*16-44-4=48-44-4=0
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Thus the second equation must also be 0 when x=4
|dw:1348118755000:dw| lol btw that's not what the functions look like, but you have to make them touch each other
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