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Find the center-radius form of the equation of the circle. center (-2, 0), radius = square root of 2
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(x-x_1)^2 +(y-y_1)^2 = r^2 x_1 = -2, y_1 = 0, and r = sqrt(2)
can you do it now?
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oh yes i got it now thank you!!!
what you get for an answer
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(x + 2)^2 + y^2=sqrt2 is that right
@caroesfea (x + 2)^2 + y^2=(sqrt2)^2 = 2 (x + 2)^2 + y^2 = 2 --> Don't forget to square the radius
@Directrix thank you!
Glad to help.
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