a bus is travelling with 52 passenger. when it arrives at a stop, "y" passengers get off & 4 get on. at the next stop, one-third of the passengers get off & 4 get on. there are now 25 passengers. find "y"

Question

anonymous · Answer

after first stop the number of passengers is :52 -y +4
second stop: (52 -y +4) - (52 -y +4) * (1/3) + 4 = 25

so we have to solve : 
(52 -y +4) - (52 -y +4) * (1/3) + 4 = 25

anonymous · Answer

can you do it ?

anonymous · Answer

yeah

anonymous · Answer

but why is (52-y+4) written twice?

anonymous · Answer

at the second stop there was (52 -y +4) passengers
and you have been told that 1/3 of them get off
so we have to subtract (52 -y +4) * (1/3)

anonymous · Answer

dont ignore the fact that it is multiplied by 1/3

anonymous · Answer

so what do we do?

anonymous · Answer

(52 -y +4) - (52 -y +4) * (1/3) + 4 = 25  solve this!

anonymous · Answer

(52 -y +4) - (52 -y +4) * (1/3)=25-4=21..then?

anonymous · Answer

...?