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OpenStudy (anonymous):
how i find this integral...
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OpenStudy (anonymous):
?
OpenStudy (anonymous):
OpenStudy (anonymous):
1+tan^2 = (1/cos^2) does this help ?
OpenStudy (anonymous):
hmmm i will try
OpenStudy (anonymous):
4sinxcosx my answer ?
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OpenStudy (anonymous):
inside the integral .. now you know how to integrate it ?
OpenStudy (anonymous):
yes i know...
OpenStudy (anonymous):
good :)
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