Ask your own question, for FREE!
Mathematics 10 Online
OpenStudy (anonymous):

a_n=a_(n-1+2) , n>=2

OpenStudy (anonymous):

isn't that the same thing ? \[a_n=a_{n-1}+2\]

OpenStudy (anonymous):

what is ur \(a_1\)

OpenStudy (anonymous):

means

OpenStudy (anonymous):

do u want to find the general formula for sequence \(a_n\) ?

OpenStudy (anonymous):

no want to find recurrence relations

OpenStudy (anonymous):

mm recursion

OpenStudy (anonymous):

no but its \[a_{n}=a_{n-1+2}, n \ge 2\]

OpenStudy (anonymous):

it means\[a_n=a_{n+1}\]so the recurrence is a constant

OpenStudy (anonymous):

so how can i solved it??

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!