Question

Find the area of the trapezoid shown.

Answer 1

1/2 *8 *4 sin(60) + 4*12 +1/2*4*4

Answer 2

The area for the right triangle at the left is 1/2 *8*4 *sin(60) where 60 is the angle b/n the sides with length 8 and 4.

Answer 3

Okay. So the equation is 1/2 *8 *4 sin(60) + 4*12 +1/2*4*4
?

Answer 4

And the area of the 4 by 12 rectangle is 12*4

Answer 5

48 is the area of the rectangle, plus the area of the triangle= Area of Trapezoid?

Answer 6

nope
Finally the right triangle at the right of the trapezoid (16-12)*4

Answer 7

16 + 48 +area of triangle?

Answer 8

sorry 1/2*(16-12)*4

Answer 9

So 8?

Answer 10

yes thus the area is
16sin(60) + 48 +8

Answer 11

51?

Answer 12

Nope 8*3^(1/2) +56

Answer 13

That turns into a radical? @ zekarias

Answer 14

yes

Answer 15

They don't want a radical...

Answer 16

But the answer need.

Answer 17

The answer should just be a normal integer