Question

Given the triangle and equation below, what is the value of x?



sec∠C - cot∠A = 3x

Answer 1

72−62−−−−−−√=13−−√


sec∠C = 1/cos∠C =
=7/6

cot∠A = 1/tan∠A =
=13−−√/6


sec∠C - cot∠A
=(7/6)−13−−√/6

=(7−13−−√)/6


sec∠C - cot∠A = 3x
x= 1/3 (sec∠C - cot∠A )
=(1/3)[(7−13−−√)/6]

=[(7−13−−√)/18]

Answer 2

the answer is A

Answer 3

did that help?:)

Answer 4

yes, thank you so much!!:)