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What is the quotient: (64y3 + 20y2 – 28y) ÷ 4y ? 16y2 – 5y + 7 16y3 + 5y2 – 7y 16y2 + 5y – 7 16y2 – 5y – 7
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try separating the numerator: \[\implies \frac{64y^3}{4y} + \frac{20y^2}{4y} - \frac{28y}{4y}\] does that help?
how do i get 16?
oh, i divide it
yes. very perceptive
would it be 16y 2 or 3?
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B?
what is y^3 divided by y? y^2 or y^3?
3rd?
yes
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