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Please help Solve by factoring 3x^2+19x-50=0 x=
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Are you familiar with the general solution to the quadratic?
Somewhat
x = [-b +- sqrt(b^2 - 4ac)] / (2a)
Nope never seen anything like that
this one I know is supose to be done by factoring not quad
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This is for equations of the form ax^2 + bx + c = 0. Just make the substitutions and you will have your answer. Ok, just got your last comment about factoring.
Site down in three can you make an exceptino and help me with the answers to this one please
For factoring method: done by setting up (3x + 25) (x - 2)
so its 25-2
So, x = 2 or -25/3
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thank you so much
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