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Two cyclists, 90mi apart, start riding toward each other at the same time. One cycles twice as fast as the other. If they meet 2 h later, at what averge speed is each cyclist traveling?
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Let the average speed of one cyclist be x miles per hour then the average speed of the other cyclist is 2x miles per hour,
Now, According to the question, 2x*2+x*2=90
SOLVE FOR X
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