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SCORERQUS: \[\huge factorize\quad :\quad x^{ 3 }+{ 2x }^{ 2 }+{ 5x }-6 \]
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\[\huge factorize\quad :\quad x^{ 3 }+{ 2x }^{ 2 }+{ 5x }-6 \]
@satellite73
find the factors of -6: \(\pm1\) \(\pm2\) \(\pm3\) \(\pm6\)
I did tat
now put these values on the place of x.. in which case you get 0 ?
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kk
then
tell me the number in which you get 0..
may be x-2
No.. please check your question again.. there is a smell of some *mistake* ..
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http://www.wolframalpha.com/input/?i=factorize+%3A+x%5E3+%2B+2x%5E2+%2B+5x-6 Wolfram smells that
why so, then if m wrong correct me
lol .. I can not correct the question..
oh!
You *must* recheck it..
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