Question

Question

Answer 1

\[\huge If\quad p=\quad 1-\sqrt { 2 } \quad find\\ \huge \left\lfloor p+\frac { 1 }{ p } \right\rfloor ^3 \]

Answer 2

help!

Answer 3

@mukushla

Answer 4

can u evaluate 1/p ... u just need to rationalizing denum

Answer 5

\[p+\frac{1}{p}=1-\sqrt{2}+\frac{1}{1-\sqrt{2}}\]