Question

Objects with masses m1 = 12.0 kg and m2 = 5.00 kg are connected by a light string that passes over a frictionless pulley. If, when the system starts from rest, m2 falls 1.00 m in 1.30 s, determine the coefficient of kinetic friction between m1 and the table.

Answer 1

Have you drawn a free-body diagram?

Answer 2

work-kinetic energy
\[W = DeltaEc\]
m2*gh = 1/2m2*v^2
v^2 =2gh (1)
use equation v = at (2)
(1) and (2)
\[\sqrt{2gh}=at\]
a=3.4m/s^2
for m1: (ox) T - f =m1*a (3)
for m2; (oy)m2*g -T = m2*a (4)
take (3) + (4)
m2*g - f =a (m1 + m2)
f = m2*g - a (m1 + m2)
f =
coefficient of kinetic =f/m1*g